How do you find the derivative of #f(x)= (2x^2-x+1)/(2x-1)# using the quotient rule? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Massimiliano Jun 14, 2015 #y'=(4x^2-4x-1)/(2x-1)^2#. Explanation: In this way: #y'=((4x-1)(2x-1)-(2x^2-x+1)*2)/(2x-1)^2=# #=(8x^2-4x-2x+1-4x^2+2x-2)/(2x-1)^2=# #=(4x^2-4x-1)/(2x-1)^2#. Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1444 views around the world You can reuse this answer Creative Commons License