How much greater is (-13x^2 - 5x - 14) + (-14x^2 - 20x + 8)(−13x2−5x−14)+(−14x2−20x+8)?

1 Answer
Don't Memorise
Jun 19, 2015

answer 1: =color(red)(x^2 + 15x -22=x2+15x−22
answer 2: = color(red)(-27x^2-25x -6=−27x2−25x−6

Explanation:

There are two ways of interpreting this question

  1. How much greater is -13x^2 - 5x - 14 −13x2−5x−14 than -14x^2 - 20x + 8−14x2−20x+8

Here we need to subtract:
-13x^2 - 5x - 14 −13x2−5x−14
color(red)(+)14x^2 color(red)(+) 20x color(red)(- )8+14x2+20x−8
=color(red)(x^2 + 15x -22=x2+15x−22

2.The second way is by adding the two as addition color(green)(++ has been mentioned in the question.

-13x^2 - 5x - 14 -14x^2 - 20x + 8−13x2−5x−14−14x2−20x+8
grouping like terms
= color(red)((-13 x^2 - 14x^2)) + color(blue)((-5x - 20x)) + (-14 +8)=(−13x2−14x2)+(−5x−20x)+(−14+8)
= color(red)(-27x^2) color(blue)(-25x) -6=−27x2−25x−6

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