How do you simplify $(\frac{1}{2} + \frac{2}{5 i}) + (\frac{1}{20} - \frac{1}{5 i})$ $(1/2 + 2/(5i)) + (1/20 - 1/(5i))$ ?

Question

How do you simplify $(\frac{1}{2} + \frac{2}{5 i}) + (\frac{1}{20} - \frac{1}{5 i})$ $(1/2 + 2/(5i)) + (1/20 - 1/(5i))$ ?

1 Answer

Impact of this question

1834 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-17T21:25:58

$\frac{11}{20} + \frac{1}{5 i}$ $11/20+1/(5i)$

Explanation:

$(\frac{1}{2} + \frac{2}{5 i}) + (\frac{1}{20} - \frac{1}{5 i})$ $(1/2+2/(5i))+(1/20-1/(5i))$

We can remove the parenthesis:

$\frac{1}{2} + \frac{2}{5 i} + \frac{1}{20} - \frac{1}{5 i}$ $1/2+2/(5i)+1/20-1/(5i)$

Rearranging a bit:

$\frac{1}{2} + \frac{1}{20} + \frac{2}{5 i} - \frac{1}{5 i}$ $1/2+1/20+2/(5i)-1/(5i)$

We need to make the denominators of $\frac{1}{2}$ $1/2$ and $\frac{1}{20}$ $1/20$ alike and we can see that the denominators of $\frac{2}{5 i}$ $2/(5i)$ and $- \frac{1}{5 i}$ $-1/(5i)$ are already alike.

$\frac{1}{2} \cdot \frac{10}{10} = \frac{10}{20}$ $1/2*10/10=10/20$

So,

$\frac{1}{2} + \frac{1}{20} + \frac{2}{5 i} - \frac{1}{5 i} = \frac{10}{20} + \frac{1}{20} + \frac{2 - 1}{5 i}$ $1/2+1/20+2/(5i)-1/(5i)=10/20+1/20+(2-1)/(5i)$

$= \frac{11}{20} + \frac{1}{5 i}$ $=11/20+1/(5i)$

Science

Math

Humanities

... and beyond

How do you simplify $(\frac{1}{2} + \frac{2}{5 i}) + (\frac{1}{20} - \frac{1}{5 i})$ $(1/2 + 2/(5i)) + (1/20 - 1/(5i))$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify (12+25i)+(120−15i)(1/2 + 2/(5i)) + (1/20 - 1/(5i))?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify $(\frac{1}{2} + \frac{2}{5 i}) + (\frac{1}{20} - \frac{1}{5 i})$ $(1/2 + 2/(5i)) + (1/20 - 1/(5i))$ ?