How do you simplify $(3 a^{4} - 2 a^{2} + 5 a - 10) - (2 a^{4} + 4 a^{2} + 5 a - 2)$ $(3a^4-2a^2+5a-10)-(2a^4+4a^2+5a-2)$ ?

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Answer 1 · 2015-09-10T01:57:25

The simplify form of
$(3 a^{4} - 2 a^{2} + 5 a - 10)$ $(3a^4 - 2a^2 +5a -10)$ - $(2 a^{4} + 4 a^{2} + 5 a - 2)$ $(2a^4 +4a^2 +5a -2)$

is $a^{4} - 6 a^{2} - 8$ $a^4 -6a^2 -8$

In order to simplify
$(3 a^{4} - 2 a^{2} + 5 a - 10)$ $(3a^4 - 2a^2 +5a -10)$ - $(2 a^{4} + 4 a^{2} + 5 a - 2)$ $(2a^4 +4a^2 +5a -2)$ , you must

distribute the negative to all of $(2 a^{4} + 4 a^{2} + 5 a - 2)$ $(2a^4 +4a^2 +5a -2)$

so - $(2 a^{4} + 4 a^{2} + 5 a - 2)$ $(2a^4 +4a^2 +5a -2)$ is equal to - $2 a^{4} - 4 a^{2} - 5 a + 2$ $2a^4 -4a^2 -5a +2$

now you take

$3 a^{4} - 2 a^{2} + 5 a - 10$ $3a^4 - 2a^2 +5a -10$
- $2 a^{4} - 4 a^{2} - 5 a + 2$ $2a^4 -4a^2 -5a +2$

= $a^{4} - 6 a^{2} - 8$ $a^4 -6a^2 -8$

How do you simplify (3a4−2a2+5a−10)−(2a4+4a2+5a−2)(3a^4-2a^2+5a-10)-(2a^4+4a^2+5a-2)?