How do you simplify $\frac{x^{2} - 2 x - 8}{x^{2} + 3 x - 4}$ $(x^2-2x-8)/(x^2+3x-4)$ ?

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Answer 1 · 2015-09-14T00:43:41

It is already simplified.

You factor the trimonial in the numerator, and the denominator.

$\frac{(x - 4) (x + 2)}{(x - 1) (x + 4)}$ $((x - 4) (x + 2))/((x - 1) (x + 4))$

As you can see, there are no factors that are the same. So it is already as simple as it can be.

How do you simplify x2−2x−8x2+3x−4(x^2-2x-8)/(x^2+3x-4)?