How do you solve $\sqrt{y + 12} = 2$ $sqrt(y +12) = 2$ ?

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Answer 1 · 2015-09-19T23:05:21

$y = - 8$ $y = -8$

$\sqrt{y + 12} = 2$ $sqrt(y+12) = 2$

Solve it step-wise by isolating $y$ $y$ . First square both sides:
$y + 12 = 2^{2} = 4$ $y+12 = 2^2 = 4$

Then subtract $12$ $12$ from both sides:
$y + 12 - 12 = 4 - 12$ $y+12-12 = 4- 12$

Now we have the solution:
$y = - 8$ $y = -8$

How do you solve √y+12=2sqrt(y +12) = 2?