How do you find the derivative of #y= (sin^2(x)) / (1-cos(x))#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Dharma R. Sep 26, 2015 #-sinx# Explanation: initially #sin^2x=1-cos^2x=(1+cosx)(1-cosx) =>sin^2x/(1-cosx)=1+cosx=y# #y'=-sinx# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1469 views around the world You can reuse this answer Creative Commons License