How do you solve $x^2 – 13x = -12$ by factoring?

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Answer 1 · 2015-09-29T17:07:33

$x_1 = 1,x_2=12$

$x^2-13x+12=0$
$=>x^2-x-12x+12=0$
$=>x*(x-1)-12*(x-1)=0$
$=>(x-1)*(x-12)=0$
$=>x_1 = 1,x_2=12$

How do you solve x^2 – 13x = -12x^2 – 13x = -12 by factoring?