How do you simplify $(x^2+3x-18)/(x^2-36)$ ?

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Answer 1 · 2015-10-17T07:43:36

$(x^2+3x-18)/(x^2-36)$
= $(x^2+6x-3x-18)/((x+6)(x-6))$
= $(x(x+6)-3(x+6))/((x+6)(x-6))$
= $((x+6)(x-3))/((x+6)(x-6))$
= $(x-3)/(x-6)$

How do you simplify (x^2+3x-18)/(x^2-36)(x^2+3x-18)/(x^2-36)?