Given the functions $f(x)=x-7$ , $g(x)=x^2$ and $h(x)=(x-7)^2$ how do you find (g-f)(x) ?

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Answer 1 · 2015-10-27T13:54:51

$(g-f)(x)=x^2-x+7$

The only two functions you need here are $f(x)$ and $g(x)$ . You simply have to subtract $f(x)$ from $g(x)$ .

$color(red)(f(x)=x-7)$

$color(blue)(g(x)=x^2)$

$[1]" "(g-f)(x)=color(blue)(g(x))-color(red)(f(x))$

$[2]" "(g-f)(x)=color(blue)(x^2)-color(red)((x-7))$

$[3]" "color(magenta)((g-f)(x)=x^2-x+7)$

Given the functions f(x)=x-7f(x)=x-7 , g(x)=x^2g(x)=x^2 and h(x)=(x-7)^2h(x)=(x-7)^2 how do you find (g-f)(x) ?