How do you solve using elimination of −2x+3y=−5 and −x+6y=−1?

1 Answer
Jacob Sims
Nov 6, 2015

y=13andx=3 using elimination.

Explanation:

Elimination involves multiplying one equation to make two variable equal to each other.

When I (or you) look at this equation, we can look at either variable. What I notice is that I can multiply 3y by −2 to make them cancel eachother out.
−1x+6y=−1 ⇒−1x+6y=−1
(−2x+3y=−5)(−2)⇒4x−6y=10

As you can can see above, I have lined by each y with each other. We can add the top equation from the bottom equation. That will leave us with 3x=9. We can simplify to x=3.

Now we can plug x into either equation to solve for y. I will use −1x+6y=−1.

−1(3)+6y=−1
−3+6y=−1
6y=2
y=13andx=3

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