How do you find the critical points for $f(x)=x^3-6x^2+12x-6$ ?

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Answer 1 · 2015-11-08T01:27:37

This is a polynomial , so all derivatives exist . Next, find any x's such that $f'(x)=0$

$f'(x) = 3(x^2-4x+4)=0$

$x=2$ is the only critical point .

hope that helped

How do you find the critical points for f(x)=x^3-6x^2+12x-6 f(x)=x^3-6x^2+12x-6?