What are the intercepts of $2 y - x = 1$ $2y-x=1$ ?

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Answer 1 · 2015-11-19T15:47:40

$x-intercept \to {(- 1, 0)}_{y=0}$ $"x-intercept" -> (-1,0)_("y=0")$

$y-intercept \to {(0, \frac{1}{2})}_{x=0}$ $"y-intercept" -> (0,1/2)_("x=0")$

Given: $2 y - x = 1$ $2y-x=1$

$2 y = x + 1$ $2y =x+1$

$y = \frac{1}{2} x + \frac{1}{2}$ $y=1/2x+1/2$

Tont B

At $x = 0, y = \frac{1}{2}$ $x=0 , y= 1/2$

At $y = 0, x = - 1$ $y=0, x=-1$

So

$x-intercept \to {(- 1, 0)}_{y=0}$ $"x-intercept" -> (-1,0)_("y=0")$

$y-intercept \to {(0, \frac{1}{2})}_{x=0}$ $"y-intercept" -> (0,1/2)_("x=0")$

What are the intercepts of 2y-x=12y−x=12y-x=1?