What are the intercepts of #2y-x=1#?

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Answer 1 · 2015-11-19T15:47:40

#"x-intercept" -> (-1,0)_("y=0")#

#"y-intercept" -> (0,1/2)_("x=0")#

Given: #2y-x=1#

#2y =x+1#

#y=1/2x+1/2#

Tont B

At #x=0 , y= 1/2#

At #y=0, x=-1#

So

#"x-intercept" -> (-1,0)_("y=0")#

#"y-intercept" -> (0,1/2)_("x=0")#