How do you divide #(3x^2)/(6x - 3)#?

Question

1564 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-22T17:55:21

#x^2/(2x-1)#

You can factor in the denominator.

#6# and #3# both share the common factor of #3#, so we can extract #3# from both #6# and #3#.

#3((6x)/3-3/3)# #rArr##3(2x-1)#

Original equation: #(3x^2)/(6x-3)#

New equation: #(3(x^2))/(3(2x-1))#

The two #3#'s cancel out

#(cancel(3)(x^2))/(cancel(3)(2x-1))#

Final equation: #x^2/(2x-1)#