What is the vertex form of y=x^2 - 9x + 2 ?

1 Answer
Nov 24, 2015

Find vertex form of y = x^2 - 9x + 2

Ans: y = (x - 9/2)^2 - 73/4

Explanation:

Vertex (x, y).
x-coordinate of vertex: x = (-b/(2a)) = 9/2
y-coordinate of vertex: y = y(9/2) = (9/2)^2 - 9(9/2) + 2 =
= 81/4 - 81/2 + 2 = -81/4 + 2 = -73/4
Vertex form --> y = (x - 9/2)^2 - 73/4