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What is the vertex of $y = 3 {(3 x - 3)}^{2} + 3$ $y=3(3x-3)^2+3$ ?

1 Answer

Alan P. · Johnson Z.

Nov 24, 2015

vertex: $(1, 3)$ $(1,3)$

Explanation:

Any quadratic in the form
$XXX y = m {(x - a)}^{2} + b$ $color(white)("XXX")y=m(x-a)^2+b$
is in "vertex form" with a vertex at $(a, b)$ $(a,b)$

$y = 3 {(3 x - 3)}^{2} + 3 = 3 (3^{2} {(x - 1)}^{2}) + 3 = 27 {(x - 1)}^{2} + 3$ $y=3(3x-3)^2+3 = 3(3^2(x-1)^2)+3 = 27(x-1)^2+3$
which is in "vertex form" with vertex at $(1, 3)$ $(1,3)$

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