How do you simplify $\frac{4 - 2 (x - 1)}{x^{2} - 6 x + 9}$ $(4-2(x-1))/(x^2-6x+9)$ ?

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Answer 1 · 2015-11-26T14:49:09

$\frac{- 2}{x - 3}$ $(-2)/(x-3)$

$\frac{4 - 2 (x - 1)}{x^{2} - 6 x + 9}$ $(4-2(x-1))/(x^2-6x+9)$

$= \frac{4 - 2 x + 2}{x^{2} - 6 x + 9}$ $=(4-2x+2)/(x^2-6x+9)$

$= \frac{- 2 x + 6}{x^{2} - 6 x + 9}$ $=(-2x+6)/(x^2-6x+9$

$= \frac{- 2 (x - 3)}{(x - 3) (x - 3)}$ $=(-2(x-3))/((x-3)(x-3))$

$=(-2color(red)cancelcolor(black)((x-3)))/(color(red)cancelcolor(black)((x-3))(x-3))$

$=(-2)/(x-3)$

Note:
$(4-2(x-1))/(x^2-6x+9)$ is not the same as $((4-2)(x-1))/(x^2-6x+9)$

How do you simplify (4-2(x-1))/(x^2-6x+9)4−2(x−1)x2−6x+9(4-2(x-1))/(x^2-6x+9)?