How do you solve the following system of equations?: #-x – 2y = 12 , 12x+y=8#?
1 Answer
Dec 13, 2015
(28/23 , -152/28)#
Explanation:
Multiply the first equation by 2, to eliminate
#=> {(-x-2y= 12), (24 x + 2y = 16):}#
#=> {(-x cancel(-2y)= 12), (24 x cancel(+ 2y) = 16):}#
#=> 23x =28#
#=> (13x)/23= 28/23 => x= 28/23#
Substitute
We will use this one
Answer :