Let $u (x) = 2 x - 1$ $u(x)=2x-1$ and $w (x) = x^{2}$ $w(x)=x^2$ , how do you find u(w(-4)) and w(u(-4))?

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Let $u (x) = 2 x - 1$ $u(x)=2x-1$ and $w (x) = x^{2}$ $w(x)=x^2$ , how do you find u(w(-4)) and w(u(-4))?

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Answer 1 · 2015-12-20T03:08:12

u(w(-4))=31 w(u(-4))=81

Explanation:

w(u(-4))

$u (x) = 2 x - 1$ $u(x)=2x−1$
$u (- 4) = 2 (- 4) - 1$ $u(-4)=2(-4)−1$ (plug in -4)
$u (- 4) = - 8 - 1$ $u(-4)=-8−1$ (multiply)
$u (- 4) = - 9$ $u(-4)=-9$ (add)
$w (x) = x^{2}$ $w(x)=x^2$
$w (u (- 4)) = {(- 9)}^{2}$ $w(u(-4))=(-9)^2$ (plug u(-4)=-9 into w(x))
$w (u (- 4)) = 81$ $w(u(-4))=81$ (square)

u(w(-4))

$w (x) = x^{2}$ $w(x)=x^2$
$w (- 4) = {(- 4)}^{2}$ $w(-4)=(-4)^2$ (plug in -4)
$w (- 4) = 16$ $w(-4)=16$ (square)
$u (x) = 2 x - 1$ $u(x)=2x−1$
$u (w (- 4)) = 2 (16) - 1$ $u(w(-4))=2(16)−1$ (plug w(-4)=16 into u(x))
$u (w (- 4)) = 32 - 1$ $u(w(-4))=32−1$ (multiply)
$u (w (- 4)) = 31$ $u(w(-4))=31$ (add)

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Let $u (x) = 2 x - 1$ $u(x)=2x-1$ and $w (x) = x^{2}$ $w(x)=x^2$ , how do you find u(w(-4)) and w(u(-4))?

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Let $u (x) = 2 x - 1$ $u(x)=2x-1$ and $w (x) = x^{2}$ $w(x)=x^2$ , how do you find u(w(-4)) and w(u(-4))?