How do you factor: #y= n^2-7n+12 #? Algebra Polynomials and Factoring Monomial Factors of Polynomials 1 Answer Özgür Özer Dec 22, 2015 #y=(n-3)(n-4)# Explanation: #y=n^2-7n+12# #Delta=1# For #y=0#, #n_1=(7-sqrtDelta)/2, n_2=(7+sqrtDelta)/2# Therefore, #y=(n-3)(n-4)# Answer link Related questions What are Monomial Factors of Polynomials? How do you factor polynomials by finding the greatest common factor? How can a factoring problem be checked? How do you find the greatest common factors of variable expressions? How do you factor #3a+9b+6#? What is the greatest common factor of #a^3-3a^2+4a#? How do you factor #12xy+24xy^2+36xy^3#? How do you find the greatest common factor of #45y^{12}+30y^{10}#? How do you factor #92x^10y^4 - 54x^12y^9#? How do you factor #4x^2+x#? See all questions in Monomial Factors of Polynomials Impact of this question 2264 views around the world You can reuse this answer Creative Commons License