How do you find #(fg)(5)+f(4)# when #f(x)=(x^2)+1# and #g(x)=x-4#?

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Answer 1 · 2015-12-25T01:03:51

Answer: 43

#f(x) = x^2 + 1#

#g(x) = x-4#

To find #(fg)(5) + f(4) #

Step 1: Find #f(4)#

#f(4) = 4^2 + 1 = color(red)17#

Step 2: #(fg)(x) = (x^2 +1)(x-4)#

#(fg)(5) = (5^2 +1)(5-4)= (26)(1) = color(blue)26#

so #(fg)(5)+f(4) =color(blue)( 26 )+ color(red)(17) =43#