How do you combine $3/(x-3) - 1/x$ ?

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Answer 1 · 2016-01-02T01:46:44

Place on a common denominator for an answer of $(2x + 3)/(x^2 - 3x)$

$3/(x - 3)-1/x$

The common denominator of these fractions is $x(x-3)=x^2-3x$ .

$=3/(x-3)(x/x)-1/x((x-3)/(x-3))$

$=(3x)/(x^2 - 3x)-(x - 3)/(x^2 - 3x)$

$=(3x-(x-3))/(x^2-3x)$

Don't forget to distribute the negative.

$=(2x + 3)/(x^2 - 3x)$

How do you combine 3/(x-3) - 1/x 3/(x-3) - 1/x ?