How do you differentiate $f (x) = \frac{5}{x - 7}$ $f(x) = 5/(x-7)$ using the quotient rule?

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Answer 1 · 2016-01-06T22:24:30

$- \frac{5}{{(x - 7)}^{2}}$ $-5/(x-7)^2$

$f (x) = \frac{N (x)}{D (x)}$ $f(x)=(N(x))/(D(x))$

$f'(x)=(N'(x)*D(x)-D'(x)*N(x))/((D(x))^2)$

$f'(x)=(0*(x-7)-1*5)/(x-7)^2=-5/(x-7)^2$

How do you differentiate f(x) = 5/(x-7)f(x)=5x−7f(x) = 5/(x-7) using the quotient rule?