Question

How do you solve `log_x 6 = 0.5`?

Answer 1

You solve any simple log equation by putting the equation back into exponential form.

Explanation:

Essentially this question is asking you base `x` to exponent `1/2` is 6.

`log_x6=0.5`
To put this into exponential form, write it like `x^0.5=6`.
Which is `sqrtx=6`
The inverse operation of square root is `x^2`, so simply square both sides to get your answer.

`(sqrtx)^2=6^2`
`x=36`