Question

How do you find [f o g](2) and [gof](2)] given `f(x)=2x-1`, `g(x)=-3x`?

Answer 1

`{f@g}(2)` = ƒ(g(2))

Explanation:

`{f@g}(2)` = ƒ(g(2))
g(2) = -6
ƒ(-6) = 2x - 1
ƒ(-6) = 2(-6) - 1
ƒ(-6) = -13

ƒ(g(2)) = -13

`{(g@ƒ)(2)}` = g(ƒ(2))

ƒ(2) = 3
g(3) = -3x
g(3) = -3(3)
g(3) = -9

g(ƒ(2)) = -9