How do you find [f o g](2) and [gof](2)] given $f (x) = 2 x - 1$ $f(x)=2x-1$ , $g (x) = - 3 x$ $g(x)=-3x$ ?

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Answer 1 · 2016-01-09T03:34:43

${f \circ g} (2)$ ${f@g}(2)$ = ƒ(g(2))

${f \circ g} (2)$ ${f@g}(2)$ = ƒ(g(2))
g(2) = -6
ƒ(-6) = 2x - 1
ƒ(-6) = 2(-6) - 1
ƒ(-6) = -13

ƒ(g(2)) = -13

${(g@ƒ)(2)}$ = g(ƒ(2))

ƒ(2) = 3
g(3) = -3x
g(3) = -3(3)
g(3) = -9

g(ƒ(2)) = -9

How do you find [f o g](2) and [gof](2)] given f(x)=2x-1f(x)=2x−1f(x)=2x-1, g(x)=-3xg(x)=−3xg(x)=-3x?