What is the centroid of a triangle with corners at (2, 7 )(2,7), (1,5 )(1,5), and (7 , 5 )(7,5)?

1 Answer
Jan 10, 2016

Centroid is (10/3,17/3)(103,173)

Explanation:

For triangle with vertices (x_1,y_1), (x_2,y_2)(x1,y1),(x2,y2) and (x_3,y_3)(x3,y3)
The centroid G(x,y)G(x,y) where formula to find xx and yy is given by

x=(x_1+x_2+x_3)/3x=x1+x2+x33 and y=(y_1+y_2+y_3)/3y=y1+y2+y33

Now let us apply this to our problem.

Vertices are given as (2,7),(1,5)(2,7),(1,5) and (7,5)(7,5)

x_1=2, y_1=7x1=2,y1=7

x_2=1, y_2=5x2=1,y2=5

x_3=7,y_3=5x3=7,y3=5

x=(2+1+7)/3x=2+1+73 and y=(7+5+5)/3y=7+5+53
x=10/3x=103 and y=17/3y=173

Centroid G(x,y) = (10/3,17/3)G(x,y)=(103,173)