How do you differentiate the following parametric equation: x(t)=t/(t-4), y(t)=1+t ? Calculus Parametric Functions Derivative of Parametric Functions 1 Answer moutar Jan 10, 2016 dy/dx = dy/dt * dt/dx dy/dx = dy/dt / dx/dt dx/dt = (t-4 - t)/(t-4)^2 = -4/(t-4)^2 dy/dt=1 dy/dx = 1/(-4/(t-4)^2) = -(t-4)^2/4 Answer link Related questions How do you find the second derivative of a parametric function? How do you find derivatives of parametric functions? How do you find dy/dx for the curve x=t*sin(t), y=t^2+2 ? How do you find the equation of the tangent to the curve x=t^4+1, y=t^3+t at the point... How do you find (d^2y)/(dx^2) for the curve x=4+t^2, y=t^2+t^3 ? How do you find parametric equations of a tangent line? How do you find parametric equations for the tangent line to the curve with the given parametric... How do you find the equation of a line tangent to the curve at point t=-1 given the parametric... How do you differentiate the following parametric equation: x(t)=t^3-5t, y(t)=(t-3) ? How do you differentiate the following parametric equation: x(t)=lnt, y(t)=(t-3) ? See all questions in Derivative of Parametric Functions Impact of this question 1657 views around the world You can reuse this answer Creative Commons License