How do you find the equation of a line tangent to the curve at point #t=-1# given the parametric equations #x=t^3+2t# and #y=t^2+t+1#?
1 Answer
Feb 25, 2015
The answer is:
First of all let's find the cartesian coordinates of the point with
Than, let's find avector that is the direction of the tangent, putting
so:
And finally, remembering that the equation of a line given a point
The solution is: