What is the equation of the line normal to #f(x)=(x+1)^2# at #x=-1#?
1 Answer
Jan 17, 2016
Explanation:
The slope
and the generic line equation is:
with
- We have to find
#f'(x)# using the Chain Rule
then in
Alternatively:
It's a parabola with two cincident real roots.
The roots are
Then the vertex of the parabola it's