Normal Line to a Tangent
Key Questions
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If a tangent line has the equation
#y-y_1=m(x-x_1)# ,then the normal line at the point of contact is
#y-y_1=-1/m(x-x_1)# .
I hope that this was helpful.
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The normal line is the line that is perpendicular to the the tangent line.
If the slope of a line is
#m# then the slope of the perpendicular line is#-1/m# , this is also known as the negative reciprocal.The given equation is
#y=5/6x-9# the slope is#5/6# so the slope of the normal is#-6/5# .The point
#(x,y)->(4,8)# #y=mx+b -># Substitute in the values of#m# ,#x# and#y# #8=-6/5(4)+b# #8=-24/5+b# #24/5+8=b# #24/5+40/5=b# #64/5=b# The equation of the normal line is
#-> y=-6/5x+64/5# -
A normal line is the line perpendicular to a tangent line at the point of contact.
Questions
Derivatives
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Tangent Line to a Curve
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Normal Line to a Tangent
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Slope of a Curve at a Point
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Average Velocity
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Instantaneous Velocity
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Limit Definition of Derivative
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First Principles Example 1: x²
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First Principles Example 2: x³
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First Principles Example 3: square root of x
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Standard Notation and Terminology
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Differentiable vs. Non-differentiable Functions
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Rate of Change of a Function
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Average Rate of Change Over an Interval
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Instantaneous Rate of Change at a Point