Normal Line to a Tangent
Key Questions
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If a tangent line has the equation
y−y1=m(x−x1) ,then the normal line at the point of contact is
y−y1=−1m(x−x1) .
I hope that this was helpful.
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The normal line is the line that is perpendicular to the the tangent line.
If the slope of a line is
m then the slope of the perpendicular line is−1m , this is also known as the negative reciprocal.The given equation is
y=56x−9 the slope is56 so the slope of the normal is−65 .The point
(x,y)→(4,8) y=mx+b→ Substitute in the values ofm ,x andy 8=−65(4)+b 8=−245+b 245+8=b 245+405=b 645=b The equation of the normal line is
→y=−65x+645 -
A normal line is the line perpendicular to a tangent line at the point of contact.
Questions
Derivatives
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Tangent Line to a Curve
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Normal Line to a Tangent
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Slope of a Curve at a Point
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Average Velocity
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Instantaneous Velocity
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Limit Definition of Derivative
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First Principles Example 1: x²
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First Principles Example 2: x³
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First Principles Example 3: square root of x
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Standard Notation and Terminology
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Differentiable vs. Non-differentiable Functions
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Rate of Change of a Function
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Average Rate of Change Over an Interval
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Instantaneous Rate of Change at a Point