What is the equation of the line normal to # f(x)=xe^(sqrtx)# at # x=1#?
1 Answer
Jan 6, 2017
See the normal-inclusive graph.
Explanation:
So, the foot of the normal is P(1, e)..
Both
So, the slope of the normal is the negative reciprocal
And so, the equation to the normal at P(1, e) is
y-e=-3/3e&(-1)(x -1)#.
graph{(y-xe^(sqrtx))(y+0.245x-2.964)=0 [-10, 10, -5, 5]}