What is the equation of the normal line of $f(x)= 3x - 2x^2$ at $x=1$ ?

Question

1853 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-15T10:02:31

$y=x$

Given: $y=3x-2x^2$

Computing for the ordinate $y=1$

our point is $(1, 1)$

$f' (x)$ = slope

$f' (1)=-1$

the negative reciprocal of the slope is needed foe the Normal line.

so for the normal line $m=-1/(f' (1))=-1/-1=1$

$y-y_1=m(x-x_1)$

What is the equation of the normal line of f(x)= 3x - 2x^2f(x)= 3x - 2x^2 at x=1x=1?