Question

What is the equation of the normal line of `f(x)= e^(x^2+x-12)` at `x = 3`?

Answer 1

I found:
`y=-1/7x+10/7`

Explanation:

Here I would first find the slope `m` of the TANGENT of your function at `x=3`.
Then I would evaluate the slope `m'` of the PERPENDICULAR as:
`m'=-1/m`
Finally I would use the relationship:
`y-y_0=m'(x-x_0)` to find the required equation.
So: