What is the slope of the line normal to the tangent line of #f(x) = x^3-sqrtx # at # x= 3 #?
1 Answer
Jan 2, 2016
The slope of tangent can be found by taking the first derivative. The slope of the normal is the negative reciprocal of the slope of the tangent.
Explanation:
Slope of tangent
Slope of tangent at
Slope of tangent
Simplifying we get
The slope of normal would be the negative reciprocal of this value.
Slope of normal