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What is the equation of the normal line of $f (x) = - 2 x^{3} - 4 x^{2} + 6 x - 1$ $f(x)=-2x^3-4x^2+6x-1$ at $x = 2$ $x=2$ ?

1 Answer

Oct 31, 2016

I found: $y = \frac{1}{34} x - \frac{358}{17}$ $y=1/34x-358/17$

Explanation:

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