How do you solve #2e^(3x) = 4e^(5x)#?

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Answer 1 · 2016-01-18T01:38:36

Start by dividing both sides by #4e^(3x)# ...

#2e^(3x) = 4e^(5x)#

Divide both sides by #4e^(3x)# ...

#1/2=e^(2x)#

Now take the natural log of both sides ...

#ln(1/2)=ln(e^(2x))=2x#

#x=ln(1/2)/2=(-ln2)/2~~-0.3466#

hope that helped