How do you solve #50=600e^(-0.4x)#?

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Answer 1 · 2016-01-19T00:46:25

First, isolate the exponential function ...

#50=600e^(-0.4x)#

#e^(0.4x)=12#

Now, take the natural log of both sides ...

#ln(e^(0.4x))=ln12#

#0.4x=ln12#

#x=(ln12)/0.4~~6.2123#

hope that helped!