How do you solve $log x - log 3 = 2$ $log x - log 3 = 2$ ?

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Answer 1 · 2016-01-20T00:37:04

Use the property of logs , then exponentiate both sides of the equation ...

$log x - log 3 = 2$ $log x - log 3 = 2$

$log (\frac{x}{3}) = 2$ $log(x/3) = 2$

Assuming base 10 , exponentiate ...

$10^{log (\frac{x}{3})} = 10^{2}$ $10^log(x/3) = 10^2$

Simplify ...

$\frac{x}{3} = 100$ $x/3=100$

$x = 300$ $x=300$

Hope that helped

How do you solve log x - log 3 = 2logx−log3=2log x - log 3 = 2?