How do you solve #log x - log 3 = 2#?

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Answer 1 · 2016-01-20T00:37:04

Use the property of logs , then exponentiate both sides of the equation ...

#log x - log 3 = 2#

#log(x/3) = 2#

Assuming base 10 , exponentiate ...

#10^log(x/3) = 10^2#

Simplify ...

#x/3=100#

#x=300#

Hope that helped