How do you divide #(2-4i)/(4-3i)#?
1 Answer
Jan 27, 2016
Explanation:
Remember:
Given
We can simplify this expression by multiply by the conjugate of the denominator
Expand the expression, then combine like terms,
#= (8 -16i -12(-1))/(16-9(-1))#
#= (20 -10i)/(25)#
#= (20)/25 -(10)/25 i#
#=4/5 -2/5 i#