What is the equation of the line with slope m=6 that passes through (11,3)?

2 Answers

y=6x63

Explanation:

The standard equation of a line is y=mx+c, so we get y=6x+c.

Now, since the line passes through the point, the point has to satisfy the equation of the line. Substitute (11,3) in the equation to get:
3=6(11)+cc=63.

Thus, the equation of the line becomes y=6x63.

Jan 28, 2016

6x+y+63=0

Explanation:

SUPPOSE, THE EQUATION OF THE STRAIGHT LINE IS,
y=mx+c
where c is unknown.
now, in the problem,
m=6
and the line goes through (11,3) point.
now, by passing the equation of the straight line through (11,3) point and putting m=6 in the equation, we get,
3=(6)(11)+c
or,3=66+c
or,c=366
or,c=63
now, by putting m=6 and c=63 in the first equation, we will get the equation of the straight line.
so, the equation of the straight line is,
y=6x63
or,6x+y+63=0