What is the equation of the line with slope m= -6 that passes through (-11,3) ?

2 Answers

y = -6 x -63

Explanation:

The standard equation of a line is y = m x + c , so we get y = -6 x + c .

Now, since the line passes through the point, the point has to satisfy the equation of the line. Substitute (-11,3) in the equation to get:
3 = -6 (-11) + c => c = -63 .

Thus, the equation of the line becomes y = -6 x -63 .

Jan 28, 2016

6x+y+63=0

Explanation:

SUPPOSE, THE EQUATION OF THE STRAIGHT LINE IS,
y=mx+c
where c is unknown.
now, in the problem,
m=-6
and the line goes through (-11,3) point.
now, by passing the equation of the straight line through (-11,3) point and putting m=-6 in the equation, we get,
3=(-6)(-11)+c
or,3=66+c
or,c=3-66
or,c=-63
now, by putting m=-6 and c=-63 in the first equation, we will get the equation of the straight line.
so, the equation of the straight line is,
y=-6x-63
or,6x+y+63=0