What is the equation of the line with slope # m= -6 # that passes through # (-11,3) #?

2 Answers

# y = -6 x -63 #

Explanation:

The standard equation of a line is # y = m x + c #, so we get # y = -6 x + c #.

Now, since the line passes through the point, the point has to satisfy the equation of the line. Substitute # (-11,3) # in the equation to get:
# 3 = -6 (-11) + c => c = -63 #.

Thus, the equation of the line becomes # y = -6 x -63 #.

Jan 28, 2016

#6x+y+63=0#

Explanation:

SUPPOSE, THE EQUATION OF THE STRAIGHT LINE IS,
#y=mx+c#
where #c # is unknown.
now, in the problem,
#m=-6#
and the line goes through #(-11,3)# point.
now, by passing the equation of the straight line through #(-11,3)# point and putting #m=-6# in the equation, we get,
#3=(-6)(-11)+c#
#or,3=66+c#
#or,c=3-66#
#or,c=-63#
now, by putting #m=-6# and #c=-63# in the first equation, we will get the equation of the straight line.
so, the equation of the straight line is,
#y=-6x-63#
#or,6x+y+63=0#