How do you convert $(8.3, 4.2)$ $(8.3, 4.2)$ into polar forms?

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Answer 1 · 2016-01-29T13:46:08

$(9.302, 0.149 π)$ $(9.302,0.149pi)$

suppose,
$x = 8.3$ $x=8.3$
$y = 4.2$ $y=4.2$
now, we know,
for polar form,
$r^{2} = x^{2} + y^{2}$ $r^2=x^2+y^2$

$or, r = \sqrt[2]{x^{2} + y^{2}}$ $or,r=root(2)(x^2+y^2)$

now, by putting the value of x and y in the equation, we get

$r = \sqrt[2]{{8.3}^{2} + {4.2}^{2}}$ $r=root(2)(8.3^2+4.2^2$

$= \sqrt[2]{86.53}$ $=root(2)(86.53)$

$= 9.302$ $=9.302$

again
we know,
$θ = {tan}^{- 1} (\frac{y}{x})$ $theta=tan^(-1)(y/x)$

by putting the value of x and y on the above equation, we get,

$θ = {tan}^{- 1} (\frac{4.2}{8.3})$ $theta=tan^(-1)(4.2/8.3)$

$= 0.149 π$ $=0.149pi$

so, the polar form is ( $9.302, 0.149 π$ $9.302,0.149pi$ )

How do you convert (8.3, 4.2)(8.3,4.2)(8.3, 4.2) into polar forms?