What is the distance between #(4 ,( - 3pi)/4 )# and #(2 ,( 3 pi )/4 )#?

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Answer 1 · 2016-01-30T13:30:36

4.468

at first, we have to transform the two points into Cartesian form.
so,

suppose,
#A(4,-3pi/4)#

#B(-2,(3pi)/4)#

for A point

#x=4cos((-3pi)/4)=-2.828#

#y=4sin((-3pi)/4)=-2.828#

so, #A(-2.828,-2.828)#

for B point,

#x=2cos((3pi)/4)=-1.41#

#y=2sin((3pi)/4)=1.41#

so, #B(-1.41,1.41)#

so,

distance= #sqrt((-1.41+2.828)^2+(1.41+2.828)^2)=sqrt19.97=4.468#