How do you evaluate the definite integral #int (x+6)^2dx# from [0,4]? Calculus Introduction to Integration Formal Definition of the Definite Integral 1 Answer Maharshi Feb 12, 2016 #784/3 = 261.333# Explanation: #int (x+6)^2 = (x+6)^3 /3 | 0, 4 = (4+6)^3 /3 - 6^3 / 3 = 261.333 # Answer link Related questions What is the Formal Definition of the Definite Integral of the function #y=f(x)# over the... How do you use the definition of the definite integral? What is the integral of dy/dx? What is an improper integral? How do you calculate the double integral of #(xcos(x+y))dr# where r is the region: 0 less than... How do you apply the evaluation theorem to evaluate the integral #3t dt# over the interval [0,3]? What is the difference between an antiderivative and an integral? How do you integrate #3x^2-5x+9# from 0 to 7? Question #f27d5 How do you evaluate the definite integral #int sqrtt ln(t)dt# from 2 to 1? See all questions in Formal Definition of the Definite Integral Impact of this question 1530 views around the world You can reuse this answer Creative Commons License