How do you simplify #(-6-8i)/(4+12i) #?
1 Answer
Feb 12, 2016
Explanation:
We will multiply the numerator and the denominator by something called a "complex conjugate." It is the opposite of the current denominator.
So,
This leads to
Foil the numerators to get
Foil the denominators to get
Remember
Now, the numerator becomes
--->
--->
The denominator becomes
--->
--->
No we have
Reducing we get