A charge of $24 C$ $24 C$ passes through a circuit every $9 s$ $9 s$ . If the circuit can generate $8 W$ $8 W$ of power, what is the circuit's resistance?

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Answer 1 · 2016-02-12T22:43:45

Use: $P = I^{2} R$ $P=I^2R$ , where I is the current, and I=charge/time=24C/9s=8/3 Amps. You will find that the resistance, R = $1.125$ $1.125$ Ohms.

Use: $P = I^{2} R$ $P=I^2R$ , where I is the current, and I=charge/time=24C/9s.

Now:
$R = \frac{P}{I^{2}}$ $R = P/I^2$
P=8 Watts

$I = \frac{24 C}{9 s} = \frac{8}{3}$ $I = (24C)/(9s) = 8/3$ Amperes

$R = \frac{8}{{(\frac{8}{3})}^{2}}$ $R = 8/(8/3)^2$ Ohms = $(\frac{9}{8})$ $(9/8)$ Ohms

You will find that the resistance, R = $1.125$ $1.125$ Ohms.

A charge of 24C24 C passes through a circuit every 9s9 s. If the circuit can generate 8W8 W of power, what is the circuit's resistance?