Question

What is the angular momentum of a rod with a mass of `2 kg` and length of `6 m` that is spinning around its center at `3 Hz`?

Answer 1

`P=36 pi`

Explanation:

`"P: angular momentum"`
`omega:"angular velocity"`
`"I:moment of inertia"`
`I=m*l^2/12" for rod spinning around its center"`
`P=I*omega`
`P=(m*l^2)/12 *2*pi*f`
`P=(cancel(2)*6^2)/cancel(12) *cancel(2)*pi*cancel(3)`
`P=36 pi`