Question

Given `f(x)=8x-1`, and `g(x)=x/2` how do you find fog(x)?

Answer 1

Substitute `x/2` (which is `g(x)`) in place of `x`

`(f@g)(x)=4x-1`

Explanation:

`(f@g)(x)=f(g(x))`

Which means that wherever inside the function you see the variable `x` you should substitute it with `g(x)` Here:

`(f@g)(x)=8g(x)-1=8(x/2)-1=4x-1`

`(f@g)(x)=4x-1`