How do you find the derivative of $\frac{x^{2} - 4}{x - 1}$ $(x^2-4)/(x-1)$ ?

Question

How do you find the derivative of $\frac{x^{2} - 4}{x - 1}$ $(x^2-4)/(x-1)$ ?

1 Answer

Related questions

What is the Quotient Rule for derivatives?
How do I use the quotient rule to find the derivative?
How do you prove the quotient rule?
How do you use the quotient rule to differentiate $y = \frac{2 x^{4} - 3 x}{4 x - 1}$ $y=(2x^4-3x)/(4x-1)$ ?
How do you use the quotient rule to differentiate $y = \frac{cos (x)}{ln (x)}$ $y=cos(x)/ln(x)$ ?
How do you use the quotient rule to find the derivative of $y = tan (x)$ $y=tan(x)$ ?
How do you use the quotient rule to find the derivative of $y = \frac{x}{x^{2} + 1}$ $y=x/(x^2+1)$ ?
How do you use the quotient rule to find the derivative of $y = \frac{e^{x} + 1}{e^{x} - 1}$ $y=(e^x+1)/(e^x-1)$ ?
How do you use the quotient rule to find the derivative of $y = \frac{x - \sqrt{x}}{x^{\frac{1}{3}}}$ $y=(x-sqrt(x))/(x^(1/3))$ ?
How do you use the quotient rule to find the derivative of $y = \frac{x}{3 + e^{x}}$ $y=x/(3+e^x)$ ?

Impact of this question

2044 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-16T00:16:26

Use the quotient rule ...

Explanation:

$\frac{d}{d x} [\frac{x^{2} - 4}{x - 1}] = \frac{(x - 1) (2 x) - (x^{2} - 4) (1)}{{(x - 1)}^{2}}$ $d/dx[(x^2-4)/(x-1)]=[(x-1)(2x)-(x^2-4)(1)]/(x-1)^2$

$= \frac{2 x}{x - 1} - \frac{x^{2} - 4}{{(x - 1)}^{2}}$ $=(2x)/(x-1)-(x^2-4)/(x-1)^2$

hope that helped

Science

Math

Humanities

... and beyond

How do you find the derivative of $\frac{x^{2} - 4}{x - 1}$ $(x^2-4)/(x-1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the derivative of x2−4x−1(x^2-4)/(x-1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the derivative of $\frac{x^{2} - 4}{x - 1}$ $(x^2-4)/(x-1)$ ?