If $16 L$ $16 L$ of a gas at room temperature exerts a pressure of $6 k P a$ $6 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $2 L$ $2 L$ ?

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If $16 L$ $16 L$ of a gas at room temperature exerts a pressure of $6 k P a$ $6 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $2 L$ $2 L$ ?

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Answer 1 · 2016-03-01T22:23:06

$48 k P a$ $48 kPa$

Explanation:

When dealing with pressure-volume questions, it is important to remember that the two are inversely related.

With this in mind, if the volume of the container is reduced (like in the problem when it is changed from $16 L$ $16L$ to $2 L$ $2 L$ ) the pressure of the system must increase (granted there is no exchange of mass or change in temperature in the system).

To solve this problem, you can use an adaptation of the ideal gas equation:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

Where $P_{1}$ $P_1$ and $V_{1}$ $V_1$ are the initial pressure and volume of the system, and $P_{2}$ $P_2$ and $V_{2}$ $V_2$ are the final pressure and volume of the system.

From here, just plug in:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

$\frac{P_{1} V_{1}}{V_{2}} = P_{2}$ $(P_1V_1)/V_2=P_2$

$\frac{6 k P a \cdot 16 L}{2 L} = P_{2}$ $(6kPa*16L)/(2L)=P_2$

$P_{2} = 6 k P a \cdot 8$ $P_2=6kPa*8$

$P_{2} = 48 k P a$ $P_2=48kPa$

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If $16 L$ $16 L$ of a gas at room temperature exerts a pressure of $6 k P a$ $6 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $2 L$ $2 L$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

If 16L16 L of a gas at room temperature exerts a pressure of 6kPa6 kPa on its container, what pressure will the gas exert if the container's volume changes to 2L2 L?

1 Answer

Explanation:

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Impact of this question

If $16 L$ $16 L$ of a gas at room temperature exerts a pressure of $6 k P a$ $6 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $2 L$ $2 L$ ?