How do you differentiate $f (x) = cos (3 x - 2)$ $f(x) =cos(3x -2)$ ?

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How do you differentiate $f (x) = cos (3 x - 2)$ $f(x) =cos(3x -2)$ ?

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Answer 1 · 2016-03-07T10:18:02

$\frac{d f}{d x} = - 3 sin (3 x - 2)$ $(df)/dx = -3sin(3x-2)$

Explanation:

Use substitution.

If you have a function like this, let,say, $t = 3 x - 2$ $t =3x -2$
Then $f (t) = cos t$ $f(t) = cost$ and $\frac{d f}{d t} = - sin t$ $(df)/dt = -sint$
$\frac{d t}{d x} = 3$ $(dt)/dx = 3$
$\frac{d f}{d x} = \frac{d f}{d t} \cdot \frac{d t}{d x} = - sin t \cdot 3$ $(df)/dx = (df)/dt*(dt)/dx = -sint*3$

$\frac{d f}{d x} = - 3 sin (3 x - 2)$ $(df)/dx = -3sin(3x-2)$

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How do you differentiate $f (x) = cos (3 x - 2)$ $f(x) =cos(3x -2)$ ?

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Explanation:

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Science

Math

Humanities

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How do you differentiate f(x) =cos(3x -2) f(x)=cos(3x−2) f(x) =cos(3x -2) ?

1 Answer

Explanation:

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Impact of this question

How do you differentiate $f (x) = cos (3 x - 2)$ $f(x) =cos(3x -2)$ ?